Overview
What you'll learn
Distinguish exo and endo. Know the sign of ΔH, draw energy-level diagrams, and give examples of each type of reaction.
Use bond energies. Apply ΔH = (energy to break LHS bonds) − (energy to form RHS bonds) to calculate an enthalpy change.
Read energy profiles. Identify reactants, products, activation energy and ΔH on an energy profile diagram.
Explain the catalyst effect. A catalyst lowers Eₐ but does not change ΔH — and you should be able to say why.
Tutor's Insight
9.1 Energy Changes
9.1 Energy Changes
- Describe the meaning of exothermic and endothermic reactions, and the transfer of heat energy between the system and the surroundings.
- State the sign of the enthalpy change ΔH for exothermic (negative) and endothermic (positive) reactions, and represent them on energy-level diagrams.
9.1 Energy Changes
System, Surroundings & ΔH
Free Notes · O-Level Pure Chemistry
Read the full chapter
Exothermic vs endothermic, energy-level diagrams, bond breaking and forming, the bond-energy table, a worked ΔH calculation, energy profiles, catalysts and 4 worked exam questions.
9.1 Energy Changes
Exothermic vs Endothermic
Examples:
• combustion of fuels
• neutralisation (acid + alkali)
• reactive metal + water / acid
• respiration
• freezing, condensing (state changes)
Examples:
• photosynthesis
• thermal decomposition (e.g. CuCO₃ → CuO + CO₂)
• dissolving certain salts (NH₄NO₃ in water)
• melting, boiling (state changes)
9.1 Energy Changes
Energy-Level Diagrams
Label everything — Always label the axes (energy vs reaction progress), the reactants, the products and ΔH. The arrow points from reactants to products, and its direction shows the sign of ΔH.
9.2 Bond Energy & Energy Profiles
9.2 Bond Energy & Energy Profiles
- Explain that bond breaking is endothermic and bond forming is exothermic, and use bond energies to calculate the enthalpy change of a reaction.
- Interpret energy profile diagrams, identify the activation energy Eₐ and ΔH, and describe the effect of a catalyst on the activation energy.
9.2 Bond Energy & Energy Profiles
Breaking vs Forming Bonds
Result negative → forming releases more than breaking absorbed → exothermic.
Result positive → forming releases less than breaking absorbed → endothermic.
9.2 Bond Energy & Energy Profiles
Bond Energy Table
| Bond | Type | Bond energy (kJ/mol) |
|---|---|---|
| H–H | single | 436 |
| O=O | double | 496 |
| N≡N | triple | 944 |
| O–H | single | 460 |
| C–C | single | 350 |
| C=C | double | 610 |
9.2 Bond Energy & Energy Profiles
From Bonds to ΔH, in Four Steps
H₂ (g) + Cl₂ (g) → 2 HCl (g)
Bonds in reactants: 1 × H–H + 1 × Cl–Cl
Bonds in products: 2 × H–Cl
Bond energies (kJ/mol):
H–H = 436 · Cl–Cl = 242 · H–Cl = 431
- List the bonds broken (LHS) and formed (RHS).
- Energy to break the reactants: 436 + 242 = 678 kJ/mol.
- Energy released forming the products: 2 × 431 = 862 kJ/mol.
- ΔH = 678 − 862 = −184 kJ/mol. Negative → exothermic.
9.2 Bond Energy & Energy Profiles
Energy Profile Diagrams
• Eₐ = top of the hump − reactant level.
• ΔH = product level − reactant level (signed).
9.2 Bond Energy & Energy Profiles
Activation Energy & Catalysts
A catalyst lowers Eₐ but does not change ΔH. This is a favourite MCQ trap: a shorter hump on the profile does not mean a different enthalpy change — only the reactants and products decide ΔH, and the catalyst leaves them exactly where they were.
Practice
Exam-style questions
Combustion of candle wax
The conversion of candle wax (C₃₀H₆₂) into CO₂ and H₂O proceeds in four stages:
Which stages are exothermic?
A 1 and 3 B 1 and 4 C 2 and 3 D 3 and 4
- Stage 1: solid → liquid (melting). Particles overcome attractions → absorbs heat → endothermic.
- Stage 2: liquid → gas (vaporising). Endothermic, for the same reason.
- Stage 3: combustion. Stronger bonds form in CO₂ and H₂O than were in C₃₀H₆₂ and O₂ → releases heat → exothermic.
- Stage 4: gas → liquid (condensing). Bonds form between H₂O molecules → exothermic. Answer D.
Burning hydrogen
Hydrogen burns in air to form water:
2H₂ (g) + O₂ (g) → 2H₂O (l)
Which statement about the enthalpy change ΔH is correct?
- Combustion of hydrogen is exothermic — that rules out C and D.
- Exothermic means net energy is released → bond forming releases MORE than bond breaking absorbed.
- i.e. energy to break < energy to form.
- Answer B.
Hydrogenation of ethyne
Ethyne reacts with hydrogen to form ethane:
C₂H₂ + 2H₂ → C₂H₆
Bond energies (kJ/mol):
C–H = 413 · C–C = 347 · C≡C = 839 · H–H = 432
What is ΔH for the reaction?
A +51 B −176 C −296 D −728 kJ/mol
- Break (LHS): C₂H₂ has 2 C–H + 1 C≡C; 2H₂ has 2 H–H. So 2(413) + 839 + 2(432) = 2529 kJ.
- Form (RHS): C₂H₆ has 6 C–H + 1 C–C. So 6(413) + 347 = 2825 kJ.
- ΔH = broken − formed = 2529 − 2825 = −296 kJ/mol.
- Negative → exothermic. Answer C.
Forming hydrogen chloride, and the catalyst
The formation of hydrogen chloride is exothermic:
H₂ (g) + Cl₂ (g) → 2HCl (g) ΔH = −184 kJ/mol
(a) State, with a reason, whether the products or the reactants are at the higher energy.
(b) A catalyst is added. State the effect on the activation energy and on ΔH.
- (a) The reactants are at the higher energy. ΔH is negative (exothermic), so the products sit at a lower energy level than the reactants — energy was released to the surroundings.
- (b) The catalyst lowers the activation energy Eₐ, so more collisions are effective and the reaction speeds up.
- (b) The catalyst does not change ΔH — the reactants and products stay at the same energies, so ΔH stays at −184 kJ/mol.
Frequently Asked Questions
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O-Level Pure Chemistry · Syllabus 6092 · Topic 9 of 12 · © 2026 Overmugged. For personal study use only.