Overview
What you'll learn
Describe fuels and crude oil. Compare fossil fuels and biofuels, explain fractional distillation, and tell complete from incomplete combustion.
Use the hydrocarbon families. Work with alkanes (substitution), alkenes (addition and the test for unsaturation), and understand cracking.
React alcohols, acids and esters. Make ethanol two ways, oxidise it to a carboxylic acid, and recognise esterification and the −COO− linkage.
Compare polymerisations. Distinguish addition from condensation — monomers, linkage, by-product and repeating unit — plus recycling and environmental impact.
Tutor's Insight
11.1 Fuels & Crude Oil
11.1 Fuels and Crude Oil
- Compare fossil fuels and biofuels — sources, combustion products, and the carbon-neutral logic of bioethanol.
- Describe fractional distillation of crude oil — the tower, each fraction's properties and uses.
11.1 Fuels
Two sources, two combustions
11.1 Crude Oil
One mixture, seven fractions
| Fraction | C atoms / molecule | Uses |
|---|---|---|
| Petroleum gas | 1–4 | Fuel for stoves & lighters |
| Petrol (gasoline) | 5–10 | Fuel for cars |
| Naphtha | 8–12 | Feedstock for chemicals & plastics |
| Kerosene | 10–16 | Fuel for jets & lamps |
| Diesel | 14–20 | Fuel for buses, lorries, trains |
| Lubricating oil | 20–50 | Polishes, waxes, lubricants |
| Bitumen | 50+ | Tar for roads & roofs |
Free Notes · O-Level Pure Chemistry
Read the full chapter
Hydrocarbons, alkanes and alkenes, cracking, the bromine test, alcohols, acids and esters, addition vs condensation polymers, and 4 worked exam questions.
11.2 Hydrocarbons
11.2 Hydrocarbons
- Describe alkanes and alkenes — general formulae, saturation, structures, naming, and the differing reactivity.
- Use the bromine test and predict cracking — distinguish alkenes from alkanes and understand why cracking matters industrially.
11.2 Hydrocarbons
A homologous series — same formula, same chemistry
meth · eth · prop · but · pent · hex · hept · oct — C1 = meth, C2 = eth, C3 = prop, C4 = but, C5 = pent, C6 = hex, C7 = hept, C8 = oct. The suffix tells the family: -ane for alkane, -ene for alkene, -ol for alcohol, -oic acid for carboxylic acid.
11.2 Hydrocarbons · Structures
Six structures worth knowing cold
11.2 Hydrocarbons · Alkanes
Alkanes — saturated and unreactive
Gases mixed in the presence of UV light. One H is replaced by one Cl, and each step replaces one more H: CH₃Cl → CH₂Cl₂ → CHCl₃ → CCl₄. The hallmark of substitution — no addition across a double bond, because alkanes don't have one to add across.
11.2 Hydrocarbons · Alkenes & Cracking
Alkenes — unsaturated and reactive
• with H₂ — Ni catalyst, 150 °C (hydrogenation).
• with Br₂(aq) — room temperature (the test).
• with H₂O (steam) — H₃PO₄, 300 °C, 60 atm (forms ethanol).
e.g. C₁₀H₂₂ → C₈H₁₈ + C₂H₄.
Why bother? Too much long-chain fraction, too little petrol; cracking matches supply to demand and produces alkenes for plastics.
11.3 Alcohols, Acids & Esters
11.3 Alcohols, Acids & Esters
- Identify and react three functional groups — −OH, −COOH and the ester linkage −COO−.
- Make ethanol two ways; oxidise it to a carboxylic acid — and recognise esterification (acid + alcohol → ester + water).
11.3 Alcohols
Two routes to ethanol
Equation: C₂H₄ + H₂O → C₂H₅OH
Pros: fast, continuous, pure product.
Cons: ethene comes from crude oil — non-renewable.
Equation: C₆H₁₂O₆ → 2 C₂H₅OH + 2 CO₂
Pros: renewable, low energy.
Cons: batch process, slow, dilute product (≤ 15 %, then distil).
11.3 Acids & Esters
From alcohol to acid to ester
Pick the diagnostic test. Acidified KMnO₄: an alcohol decolourises it (gets oxidised); a carboxylic acid does NOT. Carbonate: an acid effervesces (CO₂); an alcohol does not.
11.4 Polymers
11.4 Polymers
- Distinguish addition from condensation polymerisation — monomers, conditions, linkage, by-product.
- Draw a repeating unit — and name the linkage (amide for nylon, ester for Terylene).
11.4 Polymers · Addition
Alkenes link up, nothing leaves
Open the C=C, attach square brackets, subscript n. From a monomer CH₂=CHR, the repeating unit is −[CH₂−CHR]ₙ−. Always show the carbons that came from the C=C and the substituents — examiners look for both.
11.4 Polymers · Condensation
Two monomers, water leaves
Linkage: amide −CONH−.
By-product: H₂O (one molecule lost per linkage).
Uses: clothing, ropes, fishing line.
Linkage: ester −COO−.
By-product: H₂O.
Uses: bottles (PET), fabrics, films.
Practice
Exam-style questions
Reading the tower
Petroleum can be separated into fractions by fractional distillation. Which statement about this process is correct?
- A — Bitumen has the highest b.p., so it stays at the BOTTOM, below kerosene. ✗
- B — The top of the column is the COOLEST, so it collects the LOWEST b.p. fraction. ✗
- C — Lubricating oil (C₂₀–C₅₀) is indeed the source for polishes and waxes. ✓
- D — Mᵣ near the bottom is LARGER (long molecules). ✗ Answer: C.
Chlorine + methane — substitution
Which row shows the correct equation and condition for the reaction between chlorine and methane?
- Substitution swaps ONE H for ONE Cl per step, so CH₄ + Cl₂ → CH₃Cl + HCl. This rules out A and B.
- The reaction needs UV light to break Cl₂ into reactive chlorine atoms — gases mixed in the presence of UV.
- Aqueous chlorine wouldn't work — methane doesn't dissolve and the chlorine radicals aren't generated.
- Answer: C.
Two ways to make ethanol
In which row are both statements correct?
- A — Ethene is from cracking ✓, but fermentation gives CO₂, not O₂. ✗
- B — Hydration of ethene uses phosphoric(V) acid, H₃PO₄, as catalyst ✓, and fermentation is a slow, batch process ✓. ✓✓
- C — Hydration of ethene is ~300 °C ✓; fermentation is ~37 °C, not 100 °C. ✗
- D — Hydration uses gases (steam + ethene); fermentation is in aqueous solution. Swapped. ✗ Answer: B.
Two polymers compared
Poly(ethene) is made from ethene, while nylon is made from a diamine and a dicarboxylic acid.
(a) Name the type of polymerisation for each and state the by-product (if any).
(b) Name the linkage formed in nylon.
(c) Suggest one reason poly(ethene) waste is an environmental problem.
- (a) Poly(ethene): addition polymerisation — the C=C of many ethene monomers opens and joins, with no by-product. Nylon: condensation polymerisation — the diamine and diacid join and water (H₂O) is lost at each linkage.
- (b) Nylon contains the amide linkage, −CONH−.
- (c) Poly(ethene) is non-biodegradable, so it persists in the environment (landfill / litter) instead of breaking down. (Recycling or biodegradable alternatives reduce this.)
Frequently Asked Questions
Organic Chemistry — FAQ
O-Level Pure Chemistry · Syllabus 6092 · Topic 11 of 12 · © 2026 Overmugged. For personal study use only.